0=-4.9x^2+17x+0.6

Solution for 0=-4.9x^2+17x+0.6 equation:

0=-4.9x^2+17x+0.6

We move all terms to the left:

0-(-4.9x^2+17x+0.6)=0

We add all the numbers together, and all the variables

-(-4.9x^2+17x+0.6)=0

We get rid of parentheses

4.9x^2-17x-0.6=0

a = 4.9; b = -17; c = -0.6;
Δ = b2-4ac
Δ = -172-4·4.9·(-0.6)
Δ = 300.76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{300.76}}{2*4.9}=\frac{17-\sqrt{300.76}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{300.76}}{2*4.9}=\frac{17+\sqrt{300.76}}{9.8}
$